Bài giải phần giải mạch P2

Chapter 2, Solution 1 v = iR i = v/R = (16/5) mA = 3.2 mAChapter 2, Solution 2 p = v2/R → Chapter 2, Solution 3 R = v/i = 120/(2.5x10-3) = 48k ohms Chapter 2, Solution 4 (a) (b) i = 3/100 = 30 mA i = 3/150 = 20 mA R = v2/p = 14400/60 = 240 ohmsChapter 2, Solution 5 n = 9; l = 7; b = n + l – 1 = 15 Chapter 2, Solution 6 n = 12; l = 8; b = n + l –1 = 19Chapter 2, Solution 7...
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Bài giải phần giải mạch P2Chapter 2, Solution 1 v = iR i = v/R = (16/5) mA = 3.2 mAChapter 2, Solution 2 p = v2/R → R = v2/p = 14400/60 = 240 ohmsChapter 2, Solution 3 R = v/i = 120/(2.5x10-3) = 48k ohmsChapter 2, Solution 4 (a) i = 3/100 = 30 mA (b) i = 3/150 = 20 mAChapter 2, Solution 5 n = 9; l = 7; b = n + l – 1 = 15Chapter 2, Solution 6 n = 12; l = 8; b = n + l –1 = 19Chapter 2, Solution 7 7 elements or 7 branches and 4 nodes, as indicated. 30 V 1 20 Ω 2 3 +++- + - 2A 30 Ω 60 Ω 40 Ω 10 Ω 4Chapter 2, Solution 8 12 A a i1 8A b i3 i2 12 A c 9A d At node a, 8 = 12 + i1 i1 = - 4A At node c, 9 = 8 + i2 i2 = 1A At node d, 9 = 12 + i3 i3 = -3AChapter 2, Solution 9 Applying KCL, i1 + 1 = 10 + 2 i1 = 11A 1 + i2 = 2 + 3 i2 = 4A i2 = i3 + 3 i3 = 1AChapter 2, Solution 10 2 4A -2A i2 1 i1 3 3A At node 1, 4 + 3 = i1 i1 = 7A At node 3, 3 + i2 = -2 i2 = -5AChapter 2, Solution 11 Applying KVL to each loop gives -8 + v1 + 12 = 0 v1 = 4v -12 - v2 + 6 = 0 v2 = -6v 10 - 6 - v3 = 0 v3 = 4v -v4 + 8 - 10 = 0 v4 = -2vChapter 2, Solution 12 + 15v - loop 2 – 25v + + 10v - + v2 - + + + 20v loop 1 v1 loop 3 v3 - - - For loop 1, -20 -25 +10 + v1 = 0 v1 = 35v For loop 2, -10 +15 -v2 = 0 v2 = 5v For loop 3, -v1 +v2 +v3 = 0 v3 = 30vChapter 2, Solution 13 2A I2 7A I4 1 2 3 4 4A I1 3A I3At node 2, 3 + 7 + I2 = 0 →  I 2 = −10 AAt node 1, I1 + I 2 = 2 →  I 1 = 2 − I 2 = 12 AAt node 4, 2 = I4 + 4 →  I 4 = 2 − 4 = −2 AAt node 3, 7 + I4 = I3 →  I3 = 7 − 2 = 5 AHence,I 1 = 12 A, I 2 = −10 A, I 3 = 5 A, I 4 = −2 AChapter 2, Solution 14 + + - 3V V1 I4 V2 - I3 - + 2V - + - + V3 - + + 4V I2 - V4 I1 5V + -For mesh 1,−V4 + 2 + 5 = 0 →  V4 = 7VFor mesh 2,+4 + V3 + V4 = 0 →  V3 = −4 − 7 = −11VFor mesh 3,−3 + V1 − V3 = 0 →  V1 = V3 + 3 = −8VFor mesh 4,−V1 − V2 − 2 = 0 →  V2 = − ...