Summary of Physics doctoral thesis: The electroweak phase transition in the Zee-Babu and SU(3)C⊗SU(3)L⊗U(1)⊗U(1)N gauge models

In physics baryon asymmetry is also known as material asymmetry. This issue is currently an interesting problem. Today, to explain baryon asymmetry, scientists use two mechanisms, Leptongenesis and Baryogenesis. A model having Baryogenesis must be satisfied the three conditions of A.Sakharov.
Nội dung trích xuất từ tài liệu:
Summary of Physics doctoral thesis: The electroweak phase transition in the Zee-Babu and SU(3)C⊗SU(3)L⊗U(1)⊗U(1)N gauge models MINISTRY OF EDUCATION VIETNAM ACADEMY AND TRAINING OF SCIENCE AND TECHNOLOGY GRADUATE UNIVERSITY OF SCIENCE AND TECHNOLOGY ——————————— NGUYEN CHI THAO THE ELECTROWEAK PHASE TRANSITION IN THE ZEE-BABU AND SU (3)C ⊗ SU (3)L ⊗ U (1)X ⊗ U (1)N GAUGE MODELS Major: Theoretical and Mathematical Physics Code: 9 44 01 03 SUMMARY OF PHYSICS DOCTORAL THESIS HA NOI- 2019 The thesis is completed at: GRADUATE UNIVERSITY OF SCI- ENCE AND TECHNOLOGY VIETNAM ACADEMY OF SCIENCE AND TECHNOLOGY. Supervisors: 1. Professor Dr. Hoang Ngoc Long 2. Assoc. Prof. Dr. Phung Van Dong Reviewer 1: ........................................ Reviewer 2: ....................................... Reviewer 3: ........................................ The thesis will be defended in front of the institute doctoral the- sis Assessment Council, held at the Graduate University of Science and Technology - Vietnam Academy of Science and Technology at ... o’clock, on day ... month ... year 2019. The thesis can be found at: - The library of Graduate University of Science and Technology. - National Library of Vietnam. INTRODUCTION 1. The imperative of the thesis In physics baryon asymmetry is also known as material asym- metry. This issue is currently an interesting problem. Today, to ex- plain baryon asymmetry, scientists use two mechanisms, Leptongene- sis and Baryogenesis. A model having Baryogenesis must be satisfied the three conditions of A.Sakharov [2]. The standard model (SM) has been successful in explaining experimental results [4]. Source of CP violation in SM is smaller Baryon asymmetry of Universe (BAU) and there is no strong phase- one transition with the Higgs mass mH = 125 GeV. In other words, SM is not enough mH = 125 GeV the first order phase transition [6-8]. 2. Research targets of the thesis We want to analyze the baryon asymmetry problem and de- termine the contribution role of newl particles in some extended stan- dard models. We have done the thesis ”The electroweak phase transition in the Zee-Babu and SU (3)C⊗SU (3)L⊗U (1)⊗U (1)N gauge models” 3. The main research contents of the thesis In addition to the introduction and conclusion of the thesis, there are three chapters: Chapter 1, investigation of weak phase transition in SM. Chapter 2, investigating the weak electric phase transition in the Landau gauge and ξ gauge in the Zee-Babu model. Chapter 3, multiperiod structure of electroweak phase tran- sition in the 3-3-1-1 model. Chapter 1 OVERVIEW 1.1 The effective potential with the contribution of the scalar field The effective potential includes both thermal and quantum contributions # m4φ (χ) ¯ m2φ (χ) ¯ T4 mφ Vef f =V + 2 ln 2 + 2 F− ( ), (1.1) 64π µ 4π T in which ab T 2   −32m3 πT + 16m2 π 2 T 2 + 9m4 + 6m4 ln mφ m2 (1.2) F− ( )= T 96T 4 where m ≡ mφ ; ln[ab ] = 2 ln[4π] − 2C ≈ 3.91. 1.2 The effective potential with the contribution of the complex scalar and the gauge boson field We have a general effective formula # ! m4φ (χ) ¯ m2φ (χ) ¯ T4 mφ Vef f = V (χ) ¯ +n ln + 2 F− ( ) , (1.3) 64π 2 µ2 4π T in which n is the degrees of freedom of these two fields. 1.3 The effective potential with the contribution of the fermion field 3 1.3 The effective potential with the contribution of the fermion field We have the effective potential with the contribution of the fermion field # ! m4φ (χ) ¯ m2φ (χ) ¯ T4 mφ Vef f = V (χ) ¯ + 12 ln + F + ( ) , (1.4) 64π 2 µ2 4π 2 T in which ln[af ] = 2 ln[π] − 2C ≈ 1.14. 1.4 Effective potential in the SM The effective potential in the standard model is: m2z m2W  1 4 4 Vef f = V( χ) ¯ + 3m z ln + 6m W ln 64π 2 µ2 µ2 m2 m2t  +m4H ln H − 12m 4 t ln (1.5) µ2 µ2 T4  mz mW mH mt  + 2 3F− ( ) + 6F− ( ) + F− ( ) + 12F+ ( ) . 4π T T T T In Eq (1.5) we only consider the contribution of the t quark ...